# Retweet possible with Twitter API node?

**URL:** <https://discourse.nodered.org/t/retweet-possible-with-twitter-api-node/18033>\
**Category:** General\
**Created:** [16 November 2019 10:22 UTC](https://discourse.nodered.org/t/retweet-possible-with-twitter-api-node/18033 "2019-11-16T10:22:25Z")\
**Posts on this page:** 4\
**Page:** 1

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**Author:** ![877](https://sea2.discourse-cdn.com/flex026/user_avatar/discourse.nodered.org/877/32/8207_2.png) [@877](https://discourse.nodered.org/u/877)\
**Post date:** [16 November 2019 10:22 UTC](https://discourse.nodered.org/t/retweet-possible-with-twitter-api-node/18033/1 "2019-11-16T10:22:25Z")

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I just started using the Twitter nodes by @knolleary and was wondering if it's possible to retweet?

I'm talking a proper retweet and not a simple reposting of the original tweet.

I checked on the Twitter API page and on the github, there is an article but not sure it's relevant: [link](https://developer.twitter.com/en/docs/tweets/post-and-engage/api-reference/post-statuses-retweet-id)

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**Author:** ![877](https://sea2.discourse-cdn.com/flex026/user_avatar/discourse.nodered.org/877/32/8207_2.png) [@877](https://discourse.nodered.org/u/877)\
**Post date:** [23 November 2019 14:31 UTC](https://discourse.nodered.org/t/retweet-possible-with-twitter-api-node/18033/2 "2019-11-23T14:31:52Z")

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Anyone got an idea?

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**Author:** ![knolleary](https://sea2.discourse-cdn.com/flex026/user_avatar/discourse.nodered.org/knolleary/32/3_2.png) [@knolleary](https://discourse.nodered.org/u/knolleary)\
**Post date:** [23 November 2019 15:53 UTC](https://discourse.nodered.org/t/retweet-possible-with-twitter-api-node/18033/3 "2019-11-23T15:53:53Z")

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No, the node's don't provide a way to retweet.

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**Author:** ![877](https://sea2.discourse-cdn.com/flex026/user_avatar/discourse.nodered.org/877/32/8207_2.png) [@877](https://discourse.nodered.org/u/877)\
**Post date:** [23 November 2019 21:10 UTC](https://discourse.nodered.org/t/retweet-possible-with-twitter-api-node/18033/4 "2019-11-23T21:10:09Z")

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Darn, thanks for the answer.
