&& and || can not be combined?

[edstobi]

HI and sorry
I need again help to figure out a maybe syntax problem

if( a=="1" || b=="10" || c=="100"){ ......... working,
if( (a=="1" || b=="10" || c=="100") && d >1000){ ........is not working.

do I have a bracket problem?
THX

[cymplecy]

does changing it to (d>1000) do anything?

[edje11]

Is a,b,c and d a string or an number?

With a=="1" you a comparing a string, not a number.
d >1000 can only works with a number.

Maybe you can show where the values are coming from and what type variable they are.

if( (a==1 || b==10 || c==100) && d > 1000){
this works if all your variable are number

[edstobi]

@ edje11
a, b c are strings coming von mqtt,
d is a counter so it is a number
@cymplecy
no no change, not working

[krambriw]

This code works fine:

let a="2";
let b="3";
let c="100";
let d=1001;

if( (a=="1" || b=="10" || c=="100") && d >1000){
    msg.payload = "OK";
    return msg;    
}

If you then change to this, you won't see ok in the debug so this code is working

let a="2";
let b="3";
let c="100";
let d=1000;

if( (a=="1" || b=="10" || c=="100") && d >1000){
    msg.payload = "OK";
    return msg;    
}

[hotNipi]

@edstobi

a, b c are strings coming von mqtt,
d is a counter so it is a number

To be sure, stick this into your function.

node.warn("a is "+typeof a +", b is "+typeof b +", c is "+typeof c +", d is "+typeof d)

[edstobi]

Thanks for the tip with node.warn. My if syntax is correct only a value is a number instead of a string. So I have two strings and two numbers. With this knowledge my function is running and learned something new again!
THX