How to obtain a sequential out, from multiple outputs in a function node

[lumanga]

Dear all,
I'm really in trouble to write the easiest and solid and reliable code to do this job:
I have an Injecton node that every 1 sec. gives the output.
I need to write the code ( into the function node, or othe/others node) to have, each 1 sec. an output on only one out of function node each time, and sequentially:

To better clarify:

At Time 0: OUT from "A", after 1 sec. OUT from "B" , after 1 sec. OUT from "C after 1sec. restart to OUT from "A" and so on...

[E1cid]

You can use setTimeout and node.send
you can send to multiple outputs with node.send same format as return. To skip a output just send null in the array.
example

[{"id":"045bc0047a0505c0","type":"inject","z":"452103ea51141731","name":"every 3 seconds","props":[{"p":"payload"},{"p":"topic","vt":"str"}],"repeat":"3","crontab":"","once":false,"onceDelay":0.1,"topic":"","payload":"[\"A\",\"B\",\"C\"]","payloadType":"json","x":170,"y":1580,"wires":[["f2e806626ac988d7"]]},{"id":"f2e806626ac988d7","type":"function","z":"452103ea51141731","name":"function 13","func":"msg.payload.forEach((num, index) => {\n    let output = [null,null,null];\n    output[index] = {payload:num};   \n    setTimeout(() => {\n         node.send(output)\n    }, (index*1000))\n    \n})\nreturn null;","outputs":3,"noerr":0,"initialize":"","finalize":"","libs":[],"x":370,"y":1580,"wires":[["5f0762fc37e816eb"],["5f0762fc37e816eb"],["5f0762fc37e816eb"]]},{"id":"5f0762fc37e816eb","type":"debug","z":"452103ea51141731","name":"debug 96","active":true,"tosidebar":true,"console":false,"tostatus":false,"complete":"false","statusVal":"","statusType":"auto","x":700,"y":1440,"wires":[]}]

[lumanga]

@E1cid

payload":"[\"A\",\"B\",\"C\"]"

Dear Sir, I tank you very much...

If I wanto also to have the Payload AND the topic on the exit?

payload:["A","B","C"] and TOPIC:["aaa","bbb","ccc"]

to join the "A" with the"aaa" the "B" with "bbb"... etc, to have the 3 output with
OUTPUT 1= payload "A" and topic "aaa"
OUTPUT 2 = payload "B" and topic "bbb"
OUTPUT 3= payload "C" and topic "ccc"
Thanks in advance

[E1cid]

Then the array would need to be an array of objects, so you could define both "A" and "aaa". You would add the topic to the output in the code.

[{"id":"045bc0047a0505c0","type":"inject","z":"452103ea51141731","name":"every 3 seconds","props":[{"p":"payload"},{"p":"topic","vt":"str"}],"repeat":"3","crontab":"","once":false,"onceDelay":0.1,"topic":"","payload":"[{\"payload\":\"A\",\"topic\":\"aaa\"},{\"payload\":\"B\",\"topic\":\"bbb\"},{\"payload\":\"C\",\"topic\":\"ccc\"}]","payloadType":"json","x":190,"y":880,"wires":[["f2e806626ac988d7"]]},{"id":"f2e806626ac988d7","type":"function","z":"452103ea51141731","name":"function 13","func":"msg.payload.forEach((obj, index) => {\n    let output = [null,null,null];\n    output[index] = {payload: obj.payload,topic: obj.topic};   \n    setTimeout(() => {\n         node.send(output)\n    }, (index*1000))\n    \n})\nreturn null;","outputs":3,"noerr":0,"initialize":"","finalize":"","libs":[],"x":390,"y":880,"wires":[["5f0762fc37e816eb"],["5f0762fc37e816eb"],["5f0762fc37e816eb"]]},{"id":"5f0762fc37e816eb","type":"debug","z":"452103ea51141731","name":"debug 96","active":true,"tosidebar":true,"console":false,"tostatus":false,"complete":"false","statusVal":"","statusType":"auto","x":720,"y":740,"wires":[]}]

[edit] re-reading your question if you have ["aaa","bbb","ccc"] in msg.topic and ["A"."B","C"] in msg.payload, then you could add the topic with.

msg.payload.forEach((num, index) => {
    let output = [null,null,null];
    output[index] = {payload: num,topic: msg.topic[index]};   
    setTimeout(() => {
         node.send(output)
    }, (index*1000))
    
})
return null;