how to create function on rpi node red with two gpio - if gpio1 == 1 && gpio2 ==0 then gpio3=1 or if gpio1 == 0 && gpio2 ==1 then gpio3=0
im very new to node red. Thanks.
Sorry for bad english.
You might want to look at this https://cookbook.nodered.org/basic/join-streams
Doing simple logic operations kike this, is one of things that isn't simple to do in Node-RED for a beginner.
Please complete this table so we can give you suggestions
[edit] This table is wrong based on the original post - sorry everyone 
[/edit]
gpio1 gpio2 gpio3
0 0 ?
0 1 0
1 0 1
1 1 ?
gpio1 gpio2 gpio3
0 0 0
0 1 0
1 0 1
1 1 1
Did you look at the link @zenofmud posted? That technique will enable you to get the two input pin states into a function node.
That means gpio3 = gpio1
1 Like
And GPIO-2 is redundant.
I want to do something like that, but I'm still new. Also, my English is not very high level.
I don't know how to describe the pins in the function, what I'm showing is an example of logic, but it's not spelled correctly.
My question is how to write it correctly.
thanks
[{"id":"3f2862a8.7a553e","type":"function","z":"d4094956.4419b8","name":"","func":"if (gpio1 == 1 && gpio2 == 1) {\ngpio = 1;\n}\nelse{\n (gpio1 == 0 && gpio2 == 0){\ngpio = 0;\nreturn msg;\n}\n\n ","outputs":1,"noerr":8,"x":290,"y":140,"wires":}]
I did small projects with arduino and did fine. But things are different here.
It looks like this:
int led=13;
int high_pin=3;
int low_pin=4;
void setup() {
// put your setup code here, to run once:
pinMode(led, OUTPUT);
pinMode(high_pin, INPUT);
pinMode(low_pin, INPUT);
}
void loop() {
// put your main code here, to run repeatedly:
if (high_pin == HIGH && low_pin == HIGH) {
digitalWrite(led, HIGH);
}
else {
digitalWrite(led, LOW);
}
}
Sorry about bad english.
Did you see the link earlier about joining streams? That will allow you to get both the input gpio pins in one message.
I know this is late in the game, but I am just reading this thread.
Isn't that a misake @cymplecy? He wasn't GPIO 3 to be active if GPIO 1 and 2 are == 1.
Your second line has GPIO 3 active if GPIO 1 (ONLY) is == 1
@Trying_to_learn - ignore my private message (I've deleted it) - your right - I got my table wrong
No wonder this thread is confusing 
Don't worry.
I am the consummate at making mistakes.
1 Like
how to describe gpio in function?
I gave an example with an arduino.
It is not easy to explain to a beginner who doesn't speak English as first language.
Using logic on two separate sources is not simple to do using Node-RED
Maths and programming languages do not need knowledge of English, Chinese, Swedish, etc. The logic is clear here. This is an elementary description of the inscription of two pins, whether up or down, and a series of consequences. Plus, I'm not that new to getting to this forum.
Greetings.
@devifast - you don't describe a gpio pin in a function node. You need two gpio nodes connected to a 'join' node. That will result in having both both values from the gpio nodes in one message. You can then use a function node to test the two values and output the result to a gpio node pointing to pin 3
Hi again.
I am quickly looking at the RasPI GPIO node.
I can't find a GPIO 1
This is what I see when I open the GPIO node:
GPIO 2 and GPIO3 are there, but are maybe not the best choice to use. They look like they are used but the SPI bus.
Though if that isn't important, no problems.
For the sake of the exercise I will use GPIO 2, 3, and 4.
2 and 3 are the inputs and 4 is the output.
NOTE
the GPIO pins default to sending a 1 when not connected.
The topic nodes: they can be anything you like. I called them the GPIOx where x is the GPIO number.
Do not confuse that with the PIN number.
This flow does NOT work.
I am not smart enough to know how to do the trick where it checks if 'one' and 'two' are both set.
But I am sure you can work that bit out.
[{"id":"9a517fc5.ab935","type":"rpi-gpio in","z":"d29f28a7.551f88","name":"","pin":"3","intype":"tri","debounce":"25","read":false,"x":220,"y":2730,"wires":[["b054583c.f22a88"]]},{"id":"c9661668.04fc2","type":"rpi-gpio in","z":"d29f28a7.551f88","name":"","pin":"5","intype":"tri","debounce":"25","read":false,"x":220,"y":2770,"wires":[["180c6ef0.fa94f9"]]},{"id":"b054583c.f22a88","type":"change","z":"d29f28a7.551f88","name":"GPIO 2","rules":[{"t":"set","p":"topic","pt":"msg","to":"GPIO2","tot":"str"}],"action":"","property":"","from":"","to":"","reg":false,"x":350,"y":2730,"wires":[["3b51d656.85415a"]]},{"id":"180c6ef0.fa94f9","type":"change","z":"d29f28a7.551f88","name":"GPIO 3","rules":[{"t":"set","p":"topic","pt":"msg","to":"GPIO3","tot":"str"}],"action":"","property":"","from":"","to":"","reg":false,"x":350,"y":2770,"wires":[["3b51d656.85415a"]]},{"id":"58cde312.c6653c","type":"inject","z":"d29f28a7.551f88","name":"Test input 1 1","topic":"","payload":"1","payloadType":"num","repeat":"","crontab":"","once":false,"onceDelay":0.1,"x":200,"y":2690,"wires":[["b054583c.f22a88"]]},{"id":"5cb46292.7c2e4c","type":"inject","z":"d29f28a7.551f88","name":"Test input 2 1","topic":"","payload":"1","payloadType":"num","repeat":"","crontab":"","once":false,"onceDelay":0.1,"x":200,"y":2810,"wires":[["180c6ef0.fa94f9"]]},{"id":"1c4e2277.ee397e","type":"inject","z":"d29f28a7.551f88","name":"Test input 1 0","topic":"","payload":"0","payloadType":"num","repeat":"","crontab":"","once":false,"onceDelay":0.1,"x":200,"y":2650,"wires":[["b054583c.f22a88"]]},{"id":"5eefa522.aae874","type":"inject","z":"d29f28a7.551f88","name":"Test input 2 0","topic":"","payload":"0","payloadType":"num","repeat":"","crontab":"","once":false,"onceDelay":0.1,"x":200,"y":2850,"wires":[["180c6ef0.fa94f9"]]},{"id":"3b51d656.85415a","type":"function","z":"d29f28a7.551f88","name":"Magic happens here","func":"// Process incoming messages and store in context.\nif (msg.topic == \"GPIO2\")\n{\n context.set('one',msg.payload);\n}\nif (msg.topic == \"GPIO3\")\n{\n context.set('two',msg.payload);\n}\n\n// Set up context variables to store values.\nlet one = context.get('one') || 0;\nlet two = context.get('two') || 0;\n\nif ('one' == 1 && 'two' == 1) // You need to work on this line. As is it doesn't work.\n{\n // Create message to be on-sent.\n msg.payload = \"DO THINGS\";\n} else\n{\n return;\n //msg.payload = null;\n \n}\n\nreturn msg;\n","outputs":1,"noerr":0,"x":540,"y":2750,"wires":[["808b5691.f144e8"]]},{"id":"808b5691.f144e8","type":"debug","z":"d29f28a7.551f88","name":"","active":true,"tosidebar":true,"console":false,"tostatus":false,"complete":"false","x":750,"y":2750,"wires":[]}]
I am not a good programmer.
Please forgive my mistakes.
But I hope you see what I am trying to explain to you.
Good luck.
Look at pins 1,2,3 rather like pins x, y, z or a, b, c 1,2, and 3 are just an example.
I noticed that people take it verbatim.
Well when you discribe a situation and give an example and don't say that your example it theoretical, what do you expect?
If you want to work with two GPIO pins, then you will have two GPIO nodes and two seperate msg's. To evaluate the contents of the two messages you have to join the msg's together or you could constantly put then into two flow variables.
in eithor case you need to define what happens in all four cases - a simple truth table. The truth table you gave:
gpio1 gpio2 gpio3
0 0 0
0 1 0
1 0 1
1 1 1
says
if gpio 1 is 0 the result is 0 - gpio 2 has no effect on the result
if gpio 1 is 1 the result is 1 - gpio 2 has no effect on the result
If this is the case then you don't need to worry about gpio2. If it's not the case, then you need to correct the truth table to display the actual results you need to see.
So you eithor have a situation where
if (gpio1 == 1) {gpio3 = 1} else {gpio3 = 0}
looking at your arduino code I think your truth table should be:
gpio1 gpio2 gpio3
0 0 0
0 1 0
1 0 0
1 1 1
which would result in an if statement like:
if (gpio1 == 1 && gpio2 == 1 ) {gpio3 = 1} else {gpio3 = 0}
It's supposed to happen, but how do I write into function. Thanks
if (gpio1 == 1 && gpio2 == 1 ) {gpio3 = 1} else {gpio3 = 0}
